tentukan persamaan garis melalui titik (5,-2) dan tegak lurus garis x-3y+6=0
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Materi : Persamaan Garis Lurus
Cari Gradien
x - 3y + 6 = 0
3y = x + 6
y = ⅓x + 2 [ Gradien = ⅓ ]
Langsung saja
Titik ( x¹ = 5 dan y¹ = -2 ) dan m = ⅓
ket : TEGAK LURUS ( -1/m )
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y - y¹ = ( -1/m )( x - x¹ )
y + 2 = ( -1/⅓ )( x - 5 )
y + 2 = -3( x - 5 )
y + 2 = - 3x + 15
[ 3x + y = 13 ]
Semoga bisa membantu
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